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Solutions: Option B
As lamp X is thicker and shorter, these two factors make the resistance of X lower than Y.
Recall: Length increases, R increases & cross-sectional area increases, R decreases.
[R = pL/A]
As both bulbs are connected to the same mains, (assume 240V), the potential difference across the bulbs are 240 V.
Brightness of the bulb depends on power, P = IV or V2/R, since V is constant, I across X is higher due to lower R,hence power of X is greater than power of Y, hence X is brighter.
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